4x^2+44x-480=0

Solution for 4x^2+44x-480=0 equation:

4x^2+44x-480=0

a = 4; b = 44; c = -480;
Δ = b2-4ac
Δ = 442-4·4·(-480)
Δ = 9616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9616}=\sqrt{16*601}=\sqrt{16}*\sqrt{601}=4\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{601}}{2*4}=\frac{-44-4\sqrt{601}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{601}}{2*4}=\frac{-44+4\sqrt{601}}{8}
$